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-5x^2+2.5x+6=2x
We move all terms to the left:
-5x^2+2.5x+6-(2x)=0
We add all the numbers together, and all the variables
-5x^2+0.5x+6=0
a = -5; b = 0.5; c = +6;
Δ = b2-4ac
Δ = 0.52-4·(-5)·6
Δ = 120.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.5)-\sqrt{120.25}}{2*-5}=\frac{-0.5-\sqrt{120.25}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.5)+\sqrt{120.25}}{2*-5}=\frac{-0.5+\sqrt{120.25}}{-10} $
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